(c) the data modeled by the box plots represent the battery life of two different brands of batteries that sylvia tested.
(a) what is the median value of each data set?
(d) compare the median values of the data sets. what does this comparison tell you in terms of the situation the data represent?
(e) which battery has the greatest spread? explain how you know and identify the spread of each battery.
(a) the middle 50% of the which battery has the least spread? explain how you know and identify the spread of the middle 50% of each battery.
show work

question: what is the median value of each data set?

answer:

middle vertical line in the box is used to identify the position of median.

median of brand x = 13

median of brand y = 16

question: compare the median values of the data sets. what does this comparison tell you in terms of the situation the data represent?

answer:

we see that median of brand y is 16 which is more than median of brand x which is 13.

this comprision in terms of the situation of data tells us that brand y has more average battery life than brand x.

question: which battery has the greatest spread? explain how you know and identify the spread of each battery.

spread is found by difference between two outmost points.

for brand x, left most point = 11

for brand x, right most point = 16

then spread of brand x = 16-11= 5

for brand y, left most point = 10

for brand y, right most point = 18

then spread of brand y = 18-10= 8

hence brand y has more spread than x.

question: the middle 50% of the which battery has the least spread? explain how you know and identify the spread of the middle 50% of each battery.

answer: from box plot we can see that gapping between median and the third quartile in brand x is more than in brand y.

hence middle 50% of the battery y has the least spread.

show us the graphs dude

step-by-step explanation:

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.