Which ordered pair is not a solution of y = -4x - 9 a. (-9,27) b. (3,-21) c. (-6,15) d. (5,-28)

D. (5,-28)

Step-by-step explanation:

The slope(m) of y = -4x - 9 is -4

Finding the x and y intercepts:

When x is zero y = 0  - 9 = -9

When y is zero x = 9/-4 = -2.25

The line passes through points (-2.25,0) and (0,-9)

Taking a point (-9,27):

Slope(m) = change in y ÷ change in x = (27 - -9) ÷ (-9 - 0) = -4

Therefore the point (-9,27) is on the line.

Taking a point (3,-21):

Slope (m) = (-21 - -9) ÷ (3 - 0) = -4

Therefore a point (3,-21) is on the line.

Taking a point (-6,15):

Slope(m) = (15 - -9) ÷ (-6 - 0) = -4

Therefore a point (-6,15) is on the line.

Taking a point (5,-28):

Slope(m) = (-28 - -9) ÷ (5 - 0) = -3.8

Since the slope in this case is not -4 the point (5,-28) is not on the line.

answer: i guess 5 units?

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.