If ƒ(x ) = x^2 + 1, find ƒ(a + 1). a^2 + 2 a^2+a+1 a^2+2a+2

I'm pretty sure that this is how it goes

If ƒ(x ) = x^2 + 1, find ƒ(a + 1).

x=(a+1) so u replace x to get this:

f(a+1) = (a+1)^2+1

If you square "a" it just becomes a^2 and "1" squared is just "1"

1+1=2

a^2+2a+2

If ƒ(x ) = x^2 + 1, find ƒ(a + 1).

x=(a+1) so u replace x to get this:

f(a+1) = (a+1)^2+1

If you square "a" it just becomes a^2 and "1" squared is just "1"

1+1=2

a^2+2a+2

answer: the answer is b. i think hope i got it correct

step-by-step explanation:

d. you cannot tell because there are no values shown.