Have to find two possible rectangles for each perimeter: 20 units and need the area

One rectangle that has a length of 8, and width of 2. The area would be 16 and the perimeter would be 20.

The other rectangle has a length of 6, and width of 4. Area is 24 and perimeter is 20.

Hello!

Here are two possible rectangles with a perimeter of 20 units and their areas:



RECTANGLE #1:

The dimensions could be 2 and 8.

P = 2l + 2w

P = 2(2) + 2(8)

P = 20 units

A = l × w

A = 2 × 8

A = 16 units^2

The area would be 16 units^2.



RECTANGLE #2:

The dimensions could be 6 and 4.

P = 2l + 2w

P = 2(6) + 2(4)

P = 20 units

A = l × w

A = 6 × 4

A = 24 units^2

The area of the rectangle is 24 units^2.