Sheri’s age in 20 years time will be the same as terry’s age is now. ten years from now, terry’s age will be twice sheri’s age. what are their ages presently?

Sheri's age = 10

Terry's age = 30

Step-by-step explanation:

Sheri’s age in 20 years time will be the same as Terry’s age is now. Ten years from now.

Let T be the Terry's age

And S be the Sheri's age

Ten years from now, Terry’s age will be twice Sheri’s age

Subtract 10 from both sides

Now we replace T by 2S+10 in the first equation

Subtract S from both sides

Subtract 10 from both sides

S= 10

Sheri's age = 10

Terry's age = 30

the answer is d on edge

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240