G(x) = x3 + 6x2 + 12x + 8 determine the function’s value when x = −1. g(−1) = −3 g(−1) = 0 g(−1) = 1 g(−1) = 27

option c, g (-1) = 1

Step-by-step explanation:

The given function is g(x) = x³ + 6x² + 12x + 8

and we have to find the value of the function when x (-1) for this we will plug in the value of x = -1 in the function.

g (-1) = (-1)³ + 6 (-1)² + (12) (-1) + 8

        = (-1) + 6 - 12 + 8

       = 14 - 13

        = 1

Therefore, option c, g (-1) = 1 will be the answer.

v: l•w•h÷2.

v: 20•6•8 ÷2

v: 960÷2

v: 480