Consider the two functions given below. which of the following pairs of transformations causes the graphs of the functions to have the same y-intercept? f(x) = 4x+1 g(x) = 3^x-2 f(x) - 7 and g(x) - 4 f(x) + 1 and g(x) + 2 f(x) + 5 and g(x) + 5 f(x) - 1 and g(x) + 1

The correct answer is f(x) - 1 and g(x) + 1.

The y-intercept of f(x) is 1; it is in slope-intercept form, f(x)=mx+b, where b is the y-intercept.  1 is the b-value, so 1 is the y-intercept.

To find the y-intercept of g(x), replace x with 0:

3^0-2 = 1-2 = -1

To make them the same, you can shift f(x) down 1, -1, and g(x) up one, +1.