The smaller of two similar rectangles has dimensions 4 and 6. find the dimensions of the larger rectangle if the ratio of the perimeters is 2 to 3. 2 2/3 by 4 6 by 9 8 by 18 12 by 12

6 by 9

I was stuck on thus question too for a while but then I went back and figured everything.

The correct option is B. 6 by 9

Step-by-step explanation:

Length of the smaller rectangle = 4 units

Width of the smaller rectangle = 6 units

Perimeter of the smaller rectangle = 2 ( length + width )

                                                          = 2 (4 + 6)

                                                          = 20 units

Now, the ratio of the smaller rectangle to the larger rectangle is 2 : 3

Let the perimeter of larger rectangle be x units

⇒ 20 : x = 2 : 3

⇒ x = 10 × 3

⇒ x = 30 units

Now, Perimeter of larger rectangle = 30 units

⇒ 2 ( L + B) = 30

⇒ L + B = 15 units

Hence, from the given options only option B. gives the L + B = 15 units.

Therefore, The dimensions of larger rectangle = 6 by 9

Hence, The correct option is B. 6 by 9

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation:

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point