If a 32 ft rope is cut into two sections with one section 7 times as log as the other section, how long is teh shorter piece?

The total length of the rope = 32 ft
It is cut into two sections, say x and y
But one section is seven times the other, say y=7x (shorter section being x)
Solving for x

x+y =32
x+7x = 32
8x=32
x=32/8 = 4 ft.
Therefore, the shorter piece is 4 ft long.