Acan contains 200 mixed nuts: almonds, cashew and peanuts. if the probability of choosing an almond is 1/10 and the probability of choosing a cashew is 1/4, how many peanut are in the can?

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

cool? what is the actuall ?

step-by-step explanation: