Since computers were invented, computational speed has multiplied by a factor of 4 about every three years. if a typical computer operates with a computational speed s today, write an expression for the speed at which you can expect an equivalent computer to operate after x three-year periods.

Given that computational speed multiplies by a factor of 4 about every three years.

For computational speed today = s
Computational speed after 1 three-year period = s * 4 = s * 4^1
Computational speed after 2 three-year periods = s * 4 * 4 = s * (4^2)
Computational speed after 3 three-year periods = s * 4 * 4 * 4 = s * (4^3)
Computational speed after x three-year periods = s * (4^x)

127 millimeters is the answer

1. 3/6 or 1/22. 1/123. 1/84. 1/105. 2/12 or 1/6