Let a=x squared+4. use a to find the solutions for the following equation: (x squared + 4) squared+ 32= 12x squared+ 48 what are some solutions for x? -8, -2, 4, 0, 2, -4, 8

Your solutions are    x = -2, 0, 2======if we let      a = x² + 4then we can use "a" to find the solutions for the equation    notice how the right-hand side of the equation can be factored. we factor out a 12 from the right-hand side to get    notice that we have x² + 4 in the following locations:     we substitute those x² + 4 with "a" since we let a equal that expression.    make this into a typical quadratic equation. subtract 12a from both sides to get    find two numbers that multiply to get +32 and add to get -12.these two numbers are -8 and -4.therefore, we can factor a² - 12a + 32 into (a-8)(a-4)    by the zero factor property, the solutions occur when    if we back-substitute x² + 4 in for a, we get two more quadratic equations to solve. these are pretty easy to solve via square rooting:     your solutions are    x = -2, 0, 2

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