Together, two boys had 43 cents. the first boy spent 5 cents and the second boy spent 13 cents. the first boy’s remaining money is 2/3 of the second boy’s remaining money. how much did they each have originally?

Hello kiddio lets figure this out!

Let x = first 

y = second 

Then 

x - 5 = remainder of first 

y - 13 = remainder of second 

x - 5 = 2/3(y - 13) 

3x - 15 = 2y - 26 

3x - 2y = - 11(1) 

x + y = 43(2) 

From (2) y = 43 - x(3) 

Put (3) in (1) 

3x - 2(43 - x) = - 11 

3x - 86 + 2x = - 11 

5x = 75 

x = 15 cents 

y = 43 - 15 

= 28 cents

Have  a nice day

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128/3reason being 5 and 1/3 = 16/316/3 • 2/3 = 32/31 and 1/3 = 4/3 32/3 • 4/3 this will equal 128/3