Will mark brainliest answer! caden rolls two fair number cubes numbered from 1 to 6. he first defines the sample space, as shown below: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) based on the sample space, what is the probability of getting a total of 6? (5 points) a: 7/36 b: 5/36 c: 8/36 d: 6/36

D: 6/36

Step-by-step explanation:

As we are given the sample space, the events that sum to 6 are:

{(1,5), (2,4), (3,3),(4,2),(5,1)}

Let n(S) be the number of items in sample spae

n(S) = 36

Let E be the event the sum is 6

Then,

n(E) = 6

So,

P(Sum of two cubes is 6) = n(E) / n(S)

= 6/36

So, the correct answer is:

D: 6/36 ..

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west