Three married couples go to a movie theater. if they sit together in a row of 6 empty seats, find the probability that each woman is to the left of her husband.

Given are three married couples.

So, let us assume there are 3 men and 3 women

They are sitting in a row of 6 empty seats

There is a definite order constraint that each woman will sit left to her husband. The first woman gets 3 options to choose from 3 available seats. The second woman has two options left as already one seat is filled by the first woman. The last woman has one option left. So, it is

So, number of ways is 3! = = 6 ways.

i believe

step-by-step explanation:

from my conclusion c

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.