Mathematics, 27.07.2019 05:00 tatedason33741

Does the parabola with equation x2 – x + 4 = 0 have real or imaginary roots? 1. real, because the discriminant is positive 2. real, because the discriminant is negative 3. imaginary, because the discriminant is positive 4. imaginary, because the discriminant is negative

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Answer from: luceridiaaz

The parabola with equation $x^2\:-\:x\:+\:4\:=\:0$ has two imaginary roots, because the discriminant is negative.

Step-by-step explanation:

The quadratic formula says that the solutions are

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

for any quadratic equation like:

ax^2+bx+c=0

The discriminant is the part of the quadratic formula under the square root.

The discriminant can be positive, zero, or negative, and this determines how many solutions there are to the given quadratic equation.

A positive discriminant indicates that the quadratic has two distinct real number solutions.A discriminant of zero indicates that the quadratic has a repeated real number solution.A negative discriminant indicates that neither of the solutions are real numbers but there are two imaginary roots that are complex conjugates.

We have the parabola with equation $x^2\:-\:x\:+\:4\:=\:0$

$\mathrm{For\:}\quad a=1,\:b=-1,\:c=4:\quad x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\cdot \:1\cdot \:4}}{2\cdot \:1}$

The discriminant for this equation is $\sqrt{\left(-1\right)^2-4\cdot \:\:1\cdot \:\:4}= \sqrt{-15}$ , because the discriminant is negative the parabola has two imaginary roots.

Answer from: Quest

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Answer from: Quest

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

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Does the parabola with equation x2 – x + 4 = 0 have real or imaginary roots? 1. real, because the...