Find the area of the shaded portion in the square. show all work for full credit.
(hint: assume the central point of the arc is the corresponding corner.)

Step-by-step explanation:

In order to find the area of the shaded area you first need to find the area of the circle segment. The easiest way to do this would be to use the equation: you would substitute r with the radius which in this case is 6:

This would give you the answer

Because the picture only shows you 1/4 of the circle, you will need to divide by 4. This gives you .

Now, in order to find the area of the shaded area you will need to subtract by the area of the square. The square has side lengths of 6, and in order to find the area, you will multiply 6 by 6 to get 36.

Now you will subtract to get:

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.