Two friends leave their houses at the same time and run across town towards each other. the first friend runs at a speed of 8 miles per hour. the second friend runs at a speed of 7 miles per hour. if they left at 6 p. m. and their houses are 20 miles apart, at what time will they meet?

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1