Which equation results from applying the secant and tangent segment theorem to the figure? 12(a + 12) = 10^2 10 + 12 = a^2 10(a + 10) = 12^2 10(12) = a^2

The equation that results from applying the secant and tangent segment theorem to the figure is 12²  = 10(a+10)

According to the secant and tangent segment theorem, the square of the tangent line is equal to the product of the secant segments. Mathematically;

Tangent² = whole secant segment × External secant segment

DE² = AD × BD

Given

DE = 12

AD = a+10

BD = 10

Substitute into the formula:

12²  = 10(a+10)

Hence the equation that results from applying the secant and tangent segment theorem to the figure is 12²  = 10(a+10)

learn more on secant and tangent segment theorem here: link

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

dont think so

step-by-step explanation: