An object is launched from a platform. its height (in meters), x seconds after the launch, is modeled by: h(x)=−5x2+20x+60 what is the height of the object at the time of the launch (answer in meters)

The height of the object after x sec is modeled by :
h(x)=-5x^2+20x+60

The height of the objct at the time it was launched will be given as follows:
when the object is launched, x=0.
hence the value of h will be:
h(0)=-5(0)^2+20(0)+60
simplifying the above we get:
h(0)=60 
50 m

The reporter forgot to multiply the decimal by 100, making it 25%

Answers: the graph is translated down 1 unit and the domain and range of g(x) is the same as the domain and range of f(x).