Ascientist is studying the motion of a particular glacier. he notes that this glacier has moved 2 over 3 of a meter in 3 over 4 of a day. what is the unit rate in meter(s)/day of this glacier?

The glacier has moved 2 over 3 of a meter in 3 over 4 of a day.

Distance moved by glacier = 2 over 3 = 2/3 m

Duration in which 2/3 distance was moved = 3 over 4 of a day = 3/4 day

So we have to find unit rate in meter(s)/day.

Unit rate can be found by dividing distance moved by duration in which the distance was moved.

So finding unit rate:

We are given distance moved 2/3 and duration as 3/4.

Plugging these values in the formula for unit rate,

In division of fraction, we take reciprocal of second fraction and multiply it with the first.

Unit rate = 8/9 m/day

Answer : Unit rate at which glacier is moving is (8/9) meters per day.

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step-by-step explanation:

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh