What is the sum of all the integers between the square root of 10 and the square root of 47

First estimate the square root of 10, about 3.16
and then the square root of 47, about 6.85
now what are the integers in between 3.16 and 6.85:
4,5,6
now add them all 
4+5+6
=15
Hope this helps.

What's the square root of  10 ?
     3²=9  and  4²=16
     So  √10  is somewhere between  3  and  4 .

What's the square root of  47 ?
     6²=36  and  7²=49
     So  √47  is somewhere between 6 and 7 .

The integers between √10 and √47 are  4,  5, and  6 .

Their sum is (4 + 5 + 6) = 15 .