Ac←→ is tangent to the circle with center at b. the measure of ∠acb is 71°.

what is the measure of ∠abc?

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In the given circle, radius is perpendicular to tangent.

So that means AB⊥AC

so ∠BAC =90°(1)

Also we are given ∠ACB =71°(2)

Now we will use angle sum property of a triangle here.

It states that sum of three angles of a triangle is 180° .

Applying this property here,

∠A +∠B +∠C =180°(3)

Plugging values from equation (1) and (2) in (3)

∠A +∠B +∠C =180°

90 +∠B +71 =180°

161 + ∠B = 180°

∠B = 19°

Angle ABC is 19 degrees.

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)