On three 150-point geography tests, you earned grades of 88%, 94%, and 90%. the final test is worth 250 points. what percent do you need on the final to earn 93% of the total points on all tests?

You must earn 243 points to have earned 93% of all possible points.

We first multiply each percentage on the previous tests by 150:

0.88*150 = 132

0.94*150 = 141

0.9*150 = 135

The total number of points possible is given by adding up the possible points for the three previous tests and the 250 for the last test:

150+150+150+250 = 700

93% of the 700 points would be 0.93(700) = 651 points.

Now we have 132+141+135+x (last test) = 651

408 + x = 651

Subtract 408 from both sides:

408+x-408 = 651-408

x = 243

Step-by-step explanation:

You must earn 243 points to have earned 93% of all possible points.

We first multiply each percentage on the previous tests by 150:

0.88*150 = 132

0.94*150 = 141

0.9*150 = 135

The total number of points possible is given by adding up the possible points for the three previous tests and the 250 for the last test:

150+150+150+250 = 700

93% of the 700 points would be 0.93(700) = 651 points.

Now we have 132+141+135+x (last test) = 651

408 + x = 651

Subtract 408 from both sides:

408+x-408 = 651-408

x = 243

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w