The quadratic function f has a vertex at (3,4) and opens upward. the quadratic function g is shown below. which statement is true? g(x)=2(x-4)^2+3asap

The minimum value of f is greater than the minimum value of g.

Step-by-step explanation:

The vertex of a parabola is an extreme point of the function.

If a parabola opens upward, then vertex represent its maximum point and if a parabola opens downward, then vertex represent its minimum point.

The vertex of quadratic function f has a vertex at (3,4) and opens upward. It means the minimum value of f is 4 at x=3.

The given function is

           .... (1)

The vertex form of a parabola is

           .....(2)

Where, (h,k) is vertex and a is a constant.

On comparing (1) and (2) we get

Since a=2>1, therefore it is an upward parabola and its vertex is minimum point of the function.

The minimum value of g is 3 at x=4.

Therefore the minimum value of f is greater than the minimum value of g.

answer: idk

step-by-step explanation: