The number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate parameter of 6.4 % per hour. how many hours does it take for the size of the sample to double? note: this is a continuous exponential growth model. do not round any intermediate computations, and round your answer to the nearest hundredth.

Log(2)/log(1.064) ≈ 11.17 . . . . hours


The population can be given by
  p(n) = p₀×1.064ⁿ . . . . where n is the number of hours
You want to find n whe p(n) = 2*p₀.
  2p₀ = p₀×1.064ⁿ . . . . . . . . . . . . substitute the given information
  2 = 1.064ⁿ . . . . . . . . . . . . . . . . . divide by p₀
  log(2) = n×log(1.064) . . . . . . . . take logs to make it a linear equation
  log(2)/log(1.064) = n . . . . . . . . divide by the coefficient of n

The equation i believe is 4+ i am not sure about the part: the number of weeks in a group of days so i can't you on that part