What is the remainder when (3x3 – 2x2 + 4x – 3) is divided by (x2 + 3x + 3)?

[3x³−2x²+4x−3]/[x²+3x+3]=[(x²+3x+3)(3x−11)+28x+30]/[x²+3x+3]

=[(3x−11)]+{[28x+30]/[x²+3x+3]}

So the remainder of division is

28x+30

the answer is the option D) 28x+30

another way to make it more direct

(3x³ – 2x² + 4x – 3) is divided by║ (x² + 3x + 3)

--------------------------------------------  ║(3x-11)

-3x³-9x²-9x

--------------------------------------------

-11x²-5x-3

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+11x²+33x+33

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28x+30----------> this is the remainder

step-by-step explanation:

the true ones are a b and d