Need answers are
a. 0, 5pi/4
b. 7pi/6, 11pi/6
c. 3pi/4, 7pi/4
d. pi/4, 5pi/4

1−cos2θ/cos2θ=−3/2⋅1/cosθ

2(1−cos2θ)= −3cos θ and cosθ≠0

2−2cos2θ+3cosθ=0 and cosθ≠0

2cos2θ−3cosθ−2=0 and cosθ≠0

cosθ=3±√9+16/4 and cosθ≠0

cosθ=3±5/4 and cosθ≠0

cosθ=−1/2;cosθ=2andcosθ≠0

so the answer is 

θ=2pie /3and θ=4π/ 3

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

b. hannah is playing with her cousin at