Which equation is correct? (6 points) sec x° = opposite ÷ adjacent cosec x° = opposite ÷ adjacent cosec x° = hypotenuse ÷ opposite sec x° = adjacent ÷ hypotenuse

We know that
 see the attached figure to better understand the problem

sin x°=opposite ÷ hypotenuse
cos x°=adjacent  ÷ hypotenuse
cosec x°=1/ sin x°-------> hypotenuse ÷ opposite
sec x°=1/ cos x°-------> hypotenuse ÷ adjacent

therefore
case A) sec x° = opposite ÷ adjacent------------> is not correct
case B) cosec x° = opposite ÷ adjacent ------------> is not correct
case C) cosec x° = hypotenuse ÷ opposite ------------> is  correct
case D) sec x° = adjacent ÷ hypotenuse------------> is not correct

the answer is
the equation cosec x° = hypotenuse ÷ opposite is correct