How does the graph of g(x)=⌈x⌉+0.5 differ from the graph of f(x)=⌈x⌉? a. the graph of g(x)=⌈x⌉+0.5 is the graph of f(x)=⌈x⌉ shifted up 0.5 unit. b. the graph of g(x)=⌈x⌉+0.5 is the graph of f(x)=⌈x⌉ shifted left 0.5 unit. c. the graph of g(x)=⌈x⌉+0.5 is the graph of f(x)=⌈x⌉ shifted down 0.5 unit. d. the graph of g(x)=⌈x⌉+0.5 is the graph of f(x)=⌈x⌉ shifted right 0.5 unit.

In general, a positive constant moves a function upwards and a negative value moves it downwards. Thus, g(x)=⌈x⌉+0.5 is 0.5 units above f(x)=⌈x⌉, as shown in attached picture.

To shift a function left, you add units to the independent variable.To shift it right, you subtract a constant from "x".
Example:
h(x)=⌈x+1⌉ is 1 unit left to f(x).

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to