A(n)=−5+6(n−1)a, left parenthesis, n, right parenthesis, equals, minus, 5, plus, 6, left parenthesis, n, minus, 1, right parenthesis find the 12^ ext{th}12 th 12, start superscript, t, h, end superscript term in the sequence. answer

Given that A(n)=-5+6(n-1)a. to get the 12th term we need to substitute the values as follows;n=12thu...

Mathematics, 29.07.2019 09:00 coreyrineer2791

A(n)=−5+6(n−1)a, left parenthesis, n, right parenthesis, equals, minus, 5, plus, 6, left parenthesis, n, minus, 1, right parenthesis find the 12^\text{th}12 th 12, start superscript, t, h, end superscript term in the sequence. answer

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A(n)=−5+6(n−1)a, left parenthesis, n, right parenthesis, equals, minus, 5, plus, 6, left parenthesis...