Mathematics, 29.07.2019 10:30 nic9837
Find all solutions in the interval [0, 2π). 2 sin2x = sin x x = pi divided by three. , two pi divided by three. x = pi divided by two. , three pi divided by two. , pi divided by three. , two pi divided by three. x = 0, π, pi divided by six , five pi divided by six x = pi divided by six , five pi divided by six
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Find all solutions in the interval [0, 2π). 2 sin2x = sin x x = pi divided by three. , two pi divid...
Mathematics, 17.02.2020 18:41