F(x) = 2x2 – 4x – 3 0 = 2x2 – 4x – 3 3 = 2(x2 – 2x) 3 + 1 = 2(x2 – 2x + 1) 4 = 2(x – 1)2 2 = (x – 1)2 ± = x – 1 1 ± = x mica is solving for the zeros of a quadratic function by completing the square. her work is shown. what error did mica make? answer choices mica should have set each x = 0 instead of f(x). mica should have added 2 to 3 instead of 1. mica should have multiplied both sides by 2 instead of dividing. mica should have subtracted 1 from both sides instead of adding.

Mica should have added 2 to 3 instead of 1.

Step-by-step explanation:

f(x) = 2x^2 – 4x – 3

0 = 2x^2 – 4x – 3

Mica added 3 on boths sides and factored out 2

3 = 2(x^2 – 2x)

We have 2 outside the parenthesis , so we multiply 1 with 2  and add it one left side

3 + 1 = 2(x^2 – 2x + 1) Error in this step

The above step becomes 3 + 2 = 2(x^2 – 2x + 1)

Mica should have added 2 to 3 instead of 1.

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.