Prove that an isosceles trapezium is always cyclic

Since the opposite angles are supplementary, an isosceles trapezium is a cyclic quadrilateral. Thus, ABCD is a rectangle as each internal angle is 90°. 8. If the non-parallel sides of a trapezium are equal, prove that it is cyclic.

Idk idk idk idk idk idk idk idk

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.