Part a: explain why the x-coordinates of the points where the graphs of the equations y = 4−x and y = 2−x+1 intersect are the solutions of the equation 4−x = 2−x+1. (4 points) part b: make tables to find the solution to 4−x = 2−x+1. take the integer values of x between −2 and 2. (4 points) part c: how can you solve the equation 4−x = 2−x+1 graphically? (2 points)

You probably mean the equations are y = 4 - x and y = 2x -1. Else with given equations, the solution is not possible. The steps of the solution are listed below:

Part A) 
The solution to the equation 4 - x = 2x + 1 are the points where both the equations have same value for a given value of x. This means, if a points (x,y) lies on both the lines it will be the solution of the given equations. Since that point lies on both the lines, both lines will cross that point. Crossing that point can be seen as intersection of two lines at that point. 
Therefore, x-coordinates of the points where the graphs of equations y = 4 -  x and y = 2x + 1 intersect are the solutions of the equation 4 - x = 2x + 1

Part B)
The table is attached in the images below. As seen from the table, both lines have same value of y for x =1. So x=1 is the solution to the equation 4 - x = 2x + 1

Part C)
In order to solve the equation 4 - x = 2x + 1 , we plot the individual lines y = 4 - x and y = 2x + 1 on the graph. The point of intersection of two lines will be the solution to the equation. The graph of lines is attached below. 

B, 0.4 repeats so it is rational and square root of 16 is 4 so that is rational as well.