Solve the system of equations y=3x+30 y=8x x= ? ? y= ? ?

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y = 3x + 30
y = 8x

Since y = both the equations, we can equate them

8x = 3x + 30   {Take 3x by subtracting to the other side in order to find the value of the variable)
We do minus, when we see plus

8x - 3x = 3x - 3x + 30
3x and -3x cancels out in the right hand side

5x = 30

Divide by 5 on either side to isolate x
We do division, when we see multiplication


5 and 5 cancels out

x = 6

Now, we need to substitute x by 6 in order to find y
We can substitute in either equation, we will still get the same value

y = 8(6)
   = 48

y = 3(6) + 30
   = 18 + 30
   = 48

x = 6 , y = 48