Write the equation of the circle with center (0, 0) and (5, 2) a point on the circle.

We know that
the equation of the circle with center (0, 0) is > x²+y²=r²

Step 1
find the radius
the radius is simply the distance from the center to the point (5,2)
d=√[(5²+2²)]> d=√29
r=√29
the equation of the circle is
x²+y²=29

the answer is x²+y²=29

1. You have that:

 r²=(x-h)²+(y-k)²

 2. The center of this circle is (0,0), then:

 h=0
 k=0

 3. When you substitute the values of h and k into the equation, you have:

 r²=(x-h)²+(y-k)²
 r²=(x-0)²+(y-0)²
 r²=x²+y²

 3. Now, you must find the radius "r".

 4. You know that the point is (5,2), so:

 r²=x²+y²

 5. Finally:

 √29=x²+y²

W-14=t. that i think is the answer idk