Imagine that a lake contains two kinds of fish: trout and bass. 60% of the fish in the lake are bass and 40% are trout. if you caught 5 fish at random from this pond, which of the following would you expect to catch?
a. 0 bass and 5 trout
b. 2 bass and 3 trout
c. 3 bass and 2 trout
d. 5 bass and 0 trout

 c. 3 bass and 2 trout

Step-by-step explanation:

Given : There are two kinds of fish .

60% of the fish in the lake are bass and 40% are trout.

We can write 60% as 0.60.

If you caught 5 fish at random from this pond, then the expected number of fish in the lake are bass =

The expected number of fish in the lake are trout =

Hence, we expect to catch 3 bass and 2 trout.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

i would need to see the dot plot : )