Abasketball player makes 40% of his shots from the free throw line. suppose that each of his shots can be considered independent and that he throws 3 shots. let x = the number of shots that he makes. what is the probability that he makes 2 shots or less?

Using the binomial distribution, it is found that there is a 0.936 = 93.6% probability that he makes 2 shots or less.

-------------------

For each throw, there are only two possible outcomes. Either the player makes it, or he misses it. The probability of making a throw is independent of any other throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

In this question:

The probability of making 2 or less is the probability that he does not make all of them, that is:

In which

0.936 = 93.6% probability that he makes 2 shots or less.

A similar problem is given at link

the answer will be b x² +x-1

step-by-step explanation: