Mathematics, 28.08.2019 19:50 ash34321
The length of a pool is 3 feet more than twice its width. if the perimeter of the pool is 72 feet, find the dimensions of the pool by writing and solving a system of equations.
Answers: 2
" alt="x-length\\ y-width\\ x=2y+3\\ Perimeter: 2x+2y=72\\\\ System\ of\ equations:\\ \left \{ {{x=2y+3} \atop {2x+2y}} \right. \\ Substituting\ x=2y+3\\ 2(2y+3)+2y=72\\ 4y+6+2y=72\\ 66y=60|:6\\ y=11\\x=2y+3=2*11+3=25" />" />
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The length of a pool is 3 feet more than twice its width. if the perimeter of the pool is 72 feet, f...
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