[tex]1,\frac{1}{8},\frac{1}{27},\fr ac{1}{64}{1}{n^{3}}/tex] the denominator of the seventh term is a.] 125 b.] 216 c.] 343 d.] 513

option C) 343

Justification:

The sequence of the denominators is:

term         denominator

1               1 = 1^3
2               8 = 2^3
3               27 = 3^3
4               64 = 4^3

5               5^3 = 125
6               6^3 = 216
7               7^3 = 343

And that is the term searched. So, the answer is the option C) 343.