“find the equation of the line passing through (8,-2) & (7,-4). write your equation in point-slope and slope intercept forms. point slope form using (8,-2) point slope form using (7,-4) slope intercept form: y=2x-18

We know that
the equation of the line in point-slope>  (y – y1) = m(x – x1)
the equation of the line in slope intercept forms. >  y =mx+b

find the slope m
point (8,-2) & (7,-4).
m=(y2-y1)/(x2-x1)> (-4+2)/(7-8)=-2/-1> m=2

Part A)
find the equation of the line in point-slope using (8,-2)
(y – y1) = m(x – x1)> (y-(-2)) = 2*(x – 8)> y+2=2x-16
y=2x-16-2> y=2x-18

Part B)
find the equation of the line in point-slope using (7,-4)
(y – y1) = m(x – x1)> (y-(-4)) = 2*(x – 7)> y+4=2x-14
y=2x-14-4> y=2x-18

Part C)
find the equation of the line in slope intercept forms
using (7,-4)
y=mx+b> -4=2*7+b> -4=14+b> b=-18
then
y=2x-18

Part D)
find the equation of the line in slope intercept forms
using (8,-2)
y=mx+b> -2=2*8+b> -2=16+b> b=-18
then
y=2x-18