Which equation below will produce a decay curve y=2(4)^x y=3^x-4 y=6(1/3)^x y=1/2(3)^x

answer : y=6(1/3)^x, option C

Decay curve means when x value increases the y value will decrease.

We plug in 3 values for x and check the y value

Lets start with first option

x=0 , y= 2

x=1, y= 8

x=2, y=32

when x value increases the y value also increases. so option A is not a decay curve

x=0 , y= -4

x=1 , y= -1

x=2 , y = 5

when x value increases the y value also increases. so option B is not a decay curve.

x=0, y = 6

x=1, y = 2

x=2 , y= 0.67

when x value increases the y value decreases. so option C is a decay curve

i dont know sorry

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.