Shirley is drawing triangles that have the same area. the base of each triangle varies inversely with the height. what are the possible base and height of a second triangle if the first triangle's base is 10 and its height is 6?

1. First, you must find the constant of variation (k). The problem indicates that the base of each triangle varies inversely with the height. So, this can be represented as below:

 B=k/H

 B is the base of the triangle (B=10).
 H is the height of the triangle (H=6).
 k is the constant of variation.

 2. When you clear "k", you obtain:

 B=k/H
 k=BxH
 k=10x6
 k=60

 3. Now, you have:

 B=60/H

 4. You can give any value to "H" and you will obtain the base of the second triangle.

 5. If H=12, then:

 B=60/H
 B=60/12
 B=5

 6. Therefore, the possible base and height of a second triangle is:

 B=5
 H=12

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote