The average waiting time to be seated for dinner at a popular restaurant is 23.5 minutes with a standard deviation of 3.6 minutes assume the variable is normally distributed what is the probability that a patron will wait less than 18 minutes or more than 25 minutes

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

y=sec x is the correct answer

~batmans wife dun dun

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x