Faelyn grouped the terms and factored the gcf out of the groups of the polynomial 6x4 – 8x2 + 3x2 + 4. her work is shown. step 1: (6x4 – 8x2) + (3x2 + 4) step 2: 2x2(3x2 – 4) + 1(3x2 + 4) faelyn noticed that she does not have a common factor. which accurately describes what faelyn should do next? faelyn should realize that her work shows that the polynomial is prime. faelyn should go back and regroup the terms in step 1 as (6x4 + 3x2) – (8x2 + 4). in step 2, faelyn should factor only 2x out of the first expression. falyn should factor out a negative from one of the groups so the binomials will be the same.

Faelyn should realize that her work shows that the polynomial is prime.

Explanation:

The only difference between her factors in Step 2 is that the 4 in the first group is negative, while the 4 in the second group is positive.

Rearranging the polynomial to factor it will not change the end result.

Factoring out a negative will make not only one, but both terms, in one of the binomials the opposite sign; this will not make the factors the same.

Factoring only 2x out of the first group will result in having (3x³+4x); this is not the same either.

She should realize that when this happens, her polynomial is prime.

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all