Quadrilateral abcd is inscribed in this circle.

what is the measure of angle b?

enter your answer in the box.

m∠b=
°

∠B=157°

Step-by-step explanation:

It is given that Quadrilateral ABCD is inscribed in the circle.

Also, we know that if the Quadrilateral ABCD is inscribed in the circle, then the opposite angles of the quadrilateral are supplementary by the property of circles. Then,

∠B+∠D=180°

⇒

⇒

⇒

⇒

Thus, the value of ∠B=6x+19=6(23)+19=138+19=157°.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

x=half

step-by-step explanation: