Calculate the noon sun angles for new orleans, usa and helsinki, finland on september 22. in the answer below, new orleans answer is listed first. refer to the notes on how to calculate noon sun angles. 36.5 degrees, 6.5 degrees 60 degrees, 30 degrees 83.5 degrees 53.5 degrees

60 degrees, 30 degrees

Explanation:

Sun angle = 90° - Zenith angle

On September 22, the sun passes over celestial equator. Equinox occurs.

Zenith Angle = Latitude of the place

Latitude of New Orleans, US = 29.95° ≈ 30°

Latitude of  Helsinki, Finland = 60.95° ≈ 60°

Thus, the Sun angle at noon at New Orleans would be 90° - 30° = 60°

and at Helsinki, Finland would be 90° - 60° = 30°

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

4+4+2x

or

2x+8

step-by-step explanation: