The length of a rectangle is 6 ft longer than its width. if the perimeter of the rectangle is 52 ft , find its area.

Area=160yd

Step-by-step explanation:

let its width be w and length= w+6

2(w+6+w)=52

4w+12=52

4w=40

w=10

Area=10*(10+6)=160

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

step-by-step explanation: