The zeros of a parabola are –4 and 2, and (6, 10) is a point on the graph. which equation can be solved to determine the value of a in the equation of the parabola? 6 = a(10 – 4)(10 + 2) 6 = a(10 + 4)(10 – 2) 10 = a(6 – 4)(6 + 2) 10 = a(6 + 4)(6 – 2)

we know that

The equation of a vertical parabola is equal to

where

xi,x2 are the zeros of the quadratic equation

In this problem

the zeros of the quadratic equation are

Substitute

The equation of the parabola is equal to

The point is a point on the graph

so

the point must be satisfy the equation

Substitute the value of x and  the value of y in the equation and solve for a

therefore

the answer is the option

c

-by-step explanation:

it would be c

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: